What is (x/3-4/5)(x/3+4/5) ?

The solution to (x/3-4/5)(x/3+4/5) is ((5x-12)(5x+12))/(225)

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simplify (x/3-4/5)(x/3+4/5)

simplify

(\frac{x}{3} - \frac{4}{5}) (\frac{x}{3} + \frac{4}{5})

\frac{( 5 x - 12 ) ( 5 x + 12 )}{225}

Solution steps

(\frac{x}{3} - \frac{4}{5}) (\frac{x}{3} + \frac{4}{5})

Simplify

\frac{x}{3} - \frac{4}{5} : \frac{5 x - 12}{15}

= \frac{5 x - 12}{15} (\frac{x}{3} + \frac{4}{5})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 5 x - 12 ) ( \frac{x}{3} + \frac{4}{5} )}{15}

Simplify

(5 x - 12) (\frac{x}{3} + \frac{4}{5}) : \frac{( 5 x - 12 ) ( x \cdot 5 + 12 )}{15}

= \frac{\frac{( 5 x - 12 ) ( x \cdot 5 + 12 )}{15}}{15}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 5 x - 12 ) ( x \cdot 5 + 12 )}{15 \cdot 15}

Multiply the numbers:

15 \cdot 15 = 225

= \frac{( 5 x - 12 ) ( x \cdot 5 + 12 )}{225}

= \frac{( 5 x - 12 ) ( 5 x + 12 )}{225}

(f \circ g) x^{3} (4 x^{2} - 5 x + 9) - 1

\frac{n ^{2} + 1}{n ( n + 1 )}

(3 x - \frac{2}{9 x ^{2}})^{9}

4 (e^{2 x} + x e^{2 x})

- \frac{x ( x - 24 ) ( x ^{2} - 24 x + 152 )}{1152}

What is (x/3-4/5)(x/3+4/5) ?
The solution to (x/3-4/5)(x/3+4/5) is ((5x-12)(5x+12))/(225)