What is expand (17x-27)/((2x-3)(3x-5)) ?

The solution to expand (17x-27)/((2x-3)(3x-5)) is (17x-27)/(6x^2-19x+15)

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expand (17x-27)/((2x-3)(3x-5))

expand

\frac{17 x - 27}{( 2 x - 3 ) ( 3 x - 5 )}

\frac{17 x - 27}{6 x ^{2} - 19 x + 15}

Solution steps

\frac{17 x - 27}{( 2 x - 3 ) ( 3 x - 5 )}

Expand

(2 x - 3) (3 x - 5) : 6 x^{2} - 19 x + 15

= \frac{17 x - 27}{6 x ^{2} - 19 x + 15}

, (3 + - 4) + (6 + - 25)

\frac{- 3 s ^{4} + 24 s ^{2} + 10 k}{( s + 2 ) ^{2}}

5 (42 - 10)

\frac{2 x ^{2} + 9 x - 2}{( 2 x + 1 ) ^{2} ( 2 x - 1 )}

A + B^{^{'}} + (x + B) \cdot A

What is expand (17x-27)/((2x-3)(3x-5)) ?
The solution to expand (17x-27)/((2x-3)(3x-5)) is (17x-27)/(6x^2-19x+15)