What is expand p(3,-1)Q(-1,5) ?

The solution to expand p(3,-1)Q(-1,5) is 3(-1*5,)pQ,-1*(-1*5,)pQ

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand p(3,-1)Q(-1,5)

expand

p (3, - 1) Q (- 1, 5)

3 (- 1 \cdot 5,) pQ, - 1 \cdot (- 1 \cdot 5,) pQ

Solution steps

p (3, - 1) Q (- 1, 5)

= (3, - 1) (- 1 \cdot 5,) pQ

Apply the distributive law:

a (b - c) = ab - a c

a = pQ (- 1, 5), b = 3,, c = 1

= pQ (- 1, 5) \cdot 3, - pQ (- 1, 5) \cdot 1

= 3 (- 1 \cdot 5,) pQ, - 1 \cdot (- 1 \cdot 5,) pQ

sin (7 t) u (t - \frac{9 π}{14})

(y^{4} + 2 x y^{4} - x^{3}) d x + (4 x y^{3} + 16 x^{2} y^{3}) d y

(x + \frac{39 + 471}{5}) (x + \frac{39 - 471}{5})

\frac{( x ^{4} - 4 x ^{3} + 4 x ^{2} )}{( x + 4 ) ^{5} \cdot ( 5 - x ) ^{3}}

\frac{( y + 4 ) \cdot x}{2 + y}

What is expand p(3,-1)Q(-1,5) ?
The solution to expand p(3,-1)Q(-1,5) is 3(-1*5,)pQ,-1*(-1*5,)pQ