What is expand-((x+6)^2)/4 ?

The solution to expand-((x+6)^2)/4 is -(x^2)/4-3x-9

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expand-((x+6)^2)/4

expand

- \frac{( x + 6 ) ^{2}}{4}

- \frac{x ^{2}}{4} - 3 x - 9

Solution steps

- \frac{( x + 6 ) ^{2}}{4}

(x + 6)^{2} = x^{2} + 12 x + 36

= - \frac{x ^{2} + 12 x + 36}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} + 12 x + 36}{4} = - (\frac{x ^{2}}{4}) - (\frac{12 x}{4}) - (\frac{36}{4})

= - (\frac{x ^{2}}{4}) - (\frac{12 x}{4}) - (\frac{36}{4})

Remove parentheses:

(a) = a

= - \frac{x ^{2}}{4} - \frac{12 x}{4} - \frac{36}{4}

Divide the numbers:

\frac{12}{4} = 3

= - \frac{x ^{2}}{4} - 3 x - \frac{36}{4}

Divide the numbers:

\frac{36}{4} = 9

= - \frac{x ^{2}}{4} - 3 x - 9

(x^{2} - v^{2} x^{2}) (v d x + x d v)

\frac{z x ^{2} - z ^{2}}{4} + \frac{z ( P - z - 2 x )}{2}

(F (2) = 5 (2)^{3} - 2 (2)^{2} + 3 x - 1) (x - 1) (x + 3)

(x - 6 + 7) (x - 6 - 7)

(8 x^{2} + 4 x 4 x^{2} - 1 - 1) (1 - x)

What is expand-((x+6)^2)/4 ?
The solution to expand-((x+6)^2)/4 is -(x^2)/4-3x-9