What is expand (x^2-1)*ln(x+3) ?

The solution to expand (x^2-1)*ln(x+3) is x^2ln(x+3)-ln(x+3)

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expand (x^2-1)*ln(x+3)

expand

(x^{2} - 1) \cdot ln (x + 3)

x^{2} ln (x + 3) - ln (x + 3)

Solution steps

(x^{2} - 1) ln (x + 3)

= ln (x + 3) (x^{2} - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = ln (x + 3), b = x^{2}, c = 1

= ln (x + 3) x^{2} - ln (x + 3) \cdot 1

= x^{2} ln (x + 3) - 1 \cdot ln (x + 3)

Multiply:

1 \cdot ln (x + 3) = ln (x + 3)

= x^{2} ln (x + 3) - ln (x + 3)

sin (2 x + x)

(x - 3) (x + \frac{2}{7})

\frac{24 x ( 1 - 9 y ^{2} )}{( 3 y ^{2} + 1 ) ^{3}}

- e^{2 x} \cdot (2 e^{- 2 x} - e^{- x})

ln (e^{A (y - x)} - 1)

What is expand (x^2-1)*ln(x+3) ?
The solution to expand (x^2-1)*ln(x+3) is x^2ln(x+3)-ln(x+3)