What is expand ((12+y^2)^2)/(16) ?

The solution to expand ((12+y^2)^2)/(16) is (y^4}{16}+\frac{3y^2)/2+9

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expand ((12+y^2)^2)/(16)

expand

\frac{( 12 + y ^{2} ) ^{2}}{16}

\frac{y ^{4}}{16} + \frac{3 y ^{2}}{2} + 9

Solution steps

\frac{( 12 + y ^{2} ) ^{2}}{16}

(12 + y^{2})^{2} = 144 + 24 y^{2} + y^{4}

= \frac{144 + 24 y ^{2} + y ^{4}}{16}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{144 + 24 y ^{2} + y ^{4}}{16} = \frac{144}{16} + \frac{24 y ^{2}}{16} + \frac{y ^{4}}{16}

= \frac{144}{16} + \frac{24 y ^{2}}{16} + \frac{y ^{4}}{16}

Divide the numbers:

\frac{144}{16} = 9

= 9 + \frac{24 y ^{2}}{16} + \frac{y ^{4}}{16}

Cancel

\frac{24 y ^{2}}{16} : \frac{3 y ^{2}}{2}

= 9 + \frac{3 y ^{2}}{2} + \frac{y ^{4}}{16}

Rewrite in standard form

= \frac{y ^{4}}{16} + \frac{3 y ^{2}}{2} + 9

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A (- 3, 1, - 2, 7) B (- 1, - 4)

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What is expand ((12+y^2)^2)/(16) ?
The solution to expand ((12+y^2)^2)/(16) is (y^4}{16}+\frac{3y^2)/2+9