What is expand (dka^2-1)*(lca^2-1) ?

The solution to expand (dka^2-1)*(lca^2-1) is a^4lcdk-a^2dk-a^2lc+1

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expand (dka^2-1)*(lca^2-1)

expand

(d k a^{2} - 1) \cdot (l c a^{2} - 1)

a^{4} l c d k - a^{2} d k - a^{2} l c + 1

Solution steps

(d k a^{2} - 1) (l c a^{2} - 1)

= (a^{2} d k - 1) (a^{2} l c - 1)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = d k a^{2}, b = - 1, c = l c a^{2}, d = - 1

= d k a^{2} l c a^{2} + d k a^{2} (- 1) + (- 1) l c a^{2} + (- 1) (- 1)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= a^{2} a^{2} l c d k - 1 \cdot a^{2} d k - 1 \cdot a^{2} l c + 1 \cdot 1

Simplify

a^{2} a^{2} l c d k - 1 \cdot a^{2} d k - 1 \cdot a^{2} l c + 1 \cdot 1 : a^{4} l c d k - a^{2} d k - a^{2} l c + 1

= a^{4} l c d k - a^{2} d k - a^{2} l c + 1

(3 x^{2^{^{'}}} - 6 x + 4) (- 2 x^{2} + 7 x + 5)

(5 - \frac{y}{2})^{2}

- \frac{ln ( 1 )}{4 ( 1 ) ^{\frac{3}{2}}}

\frac{1}{j w ( 1 + j wT )}

What is expand (dka^2-1)*(lca^2-1) ?
The solution to expand (dka^2-1)*(lca^2-1) is a^4lcdk-a^2dk-a^2lc+1