What is expand-(4x^4-4x^2+5)(10x^{2/3}) ?

The solution to expand-(4x^4-4x^2+5)(10x^{2/3}) is -40x^{14/3}+40x^{8/3}-50x^{2/3}

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expand-(4x^4-4x^2+5)(10x^{2/3})

expand

- (4 x^{4} - 4 x^{2} + 5) (10 x^{\frac{2}{3}})

- 40 x^{\frac{14}{3}} + 40 x^{\frac{8}{3}} - 50 x^{\frac{2}{3}}

Solution steps

- (4 x^{4} - 4 x^{2} + 5) (10 x^{\frac{2}{3}})

= - (10 x^{\frac{2}{3}}) (4 x^{4} - 4 x^{2} + 5)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

- (10 x^{\frac{2}{3}}) (4 x^{4} - 4 x^{2} + 5) = - 10 x^{\frac{2}{3}} \cdot 4 x^{4} - 10 x^{\frac{2}{3}} (- 4 x^{2}) - 10 x^{\frac{2}{3}} \cdot 5

= - 10 x^{\frac{2}{3}} \cdot 4 x^{4} - 10 x^{\frac{2}{3}} (- 4 x^{2}) - 10 x^{\frac{2}{3}} \cdot 5

Simplify

- 10 x^{\frac{2}{3}} \cdot 4 x^{4} - 10 x^{\frac{2}{3}} (- 4 x^{2}) - 10 x^{\frac{2}{3}} \cdot 5 : - 40 x^{\frac{14}{3}} + 40 x^{\frac{8}{3}} - 50 x^{\frac{2}{3}}

= - 40 x^{\frac{14}{3}} + 40 x^{\frac{8}{3}} - 50 x^{\frac{2}{3}}

\frac{x ^{3}}{( 1 + 3 x ) ^{2}}

9 y x^{2} - 24 x y + 16 y - 6 y x^{2} + 150 y

2^{2} - 4 (2) + 4

, (60 + \frac{r}{3} - (30 + r))

x + 3 f (\frac{x ^{2}}{3} - 11)

What is expand-(4x^4-4x^2+5)(10x^{2/3}) ?
The solution to expand-(4x^4-4x^2+5)(10x^{2/3}) is -40x^{14/3}+40x^{8/3}-50x^{2/3}