What is the d/(dt)((x)(4t+3)) ?

The d/(dt)((x)(4t+3)) is (dx)/(dt)(4t+3)+4x

What is the first d/(dt)((x)(4t+3)) ?

The first d/(dt)((x)(4t+3)) is (dx)/(dt)(4t+3)+4x

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\frac{d}{d t} ((x) (4 t + 3))

\frac{d x}{d t} (4 t + 3) + 4 x

Solution steps

\frac{d}{d t} ((x) (4 t + 3))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = 4 t + 3

= \frac{d x}{d t} (4 t + 3) + \frac{d}{d t} (4 t + 3) x

\frac{d}{d t} (4 t + 3) = 4

= \frac{d x}{d t} (4 t + 3) + 4 x

(e^{x})^{2}

\frac{( 20 x ^{3} - 30 x ^{2} + 12 x - 1 ) ^{2}}{400}

- \frac{x ^{2} ( 2 x ^{6} + 7 )}{196}

(1 + csc (y))^{2}

\frac{6 ( s + 2 )}{( s ^{2} + 9 s + 20 ) ( s + 4 )}

What is the d/(dt)((x)(4t+3)) ?
The d/(dt)((x)(4t+3)) is (dx)/(dt)(4t+3)+4x
What is the first d/(dt)((x)(4t+3)) ?
The first d/(dt)((x)(4t+3)) is (dx)/(dt)(4t+3)+4x