What is expand e^{2x}*(2xe^{2x}+e^{2x}) ?

The solution to expand e^{2x}*(2xe^{2x}+e^{2x}) is 2e^{4x}x+e^{4x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand e^{2x}*(2xe^{2x}+e^{2x})

expand

e^{2 x} \cdot (2 x e^{2 x} + e^{2 x})

2 e^{4 x} x + e^{4 x}

Solution steps

e^{2 x} (2 x e^{2 x} + e^{2 x})

= e^{2 x} (2 e^{2 x} x + e^{2 x})

Apply the distributive law:

a (b + c) = ab + a c

a = e^{2 x}, b = 2 x e^{2 x}, c = e^{2 x}

= e^{2 x} \cdot 2 x e^{2 x} + e^{2 x} e^{2 x}

= 2 e^{2 x} e^{2 x} x + e^{2 x} e^{2 x}

Simplify

2 e^{2 x} e^{2 x} x + e^{2 x} e^{2 x} : 2 e^{4 x} x + e^{4 x}

= 2 e^{4 x} x + e^{4 x}

\frac{t ^{3} + 2 t ^{2} - 3 + 1}{t t}

3 sin (\frac{2 π}{365} (t - 79)) + 12

700 \cdot \frac{d}{d x} ((1 + 0.1 \cdot t)^{2} d t)

\frac{- x ^{2} - 2}{( x + 1 ) ( x - 2 )}

\frac{d}{d x} ((z) (x^{2} + 2 y^{2} + 3 z^{2} - 1))

What is expand e^{2x}*(2xe^{2x}+e^{2x}) ?
The solution to expand e^{2x}*(2xe^{2x}+e^{2x}) is 2e^{4x}x+e^{4x}