What is expand (3-x)(1/3+2/27 x^2+2/81 x^3) ?

The solution to expand (3-x)(1/3+2/27 x^2+2/81 x^3) is 1+(2x^2)/9-x/3-(2x^4)/(81)

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expand (3-x)(1/3+2/27 x^2+2/81 x^3)

expand

(3 - x) (\frac{1}{3} + \frac{2}{27} x^{2} + \frac{2}{81} x^{3})

1 + \frac{2 x ^{2}}{9} - \frac{x}{3} - \frac{2 x ^{4}}{81}

Solution steps

(3 - x) (\frac{1}{3} + \frac{2}{27} x^{2} + \frac{2}{81} x^{3})

Distribute parentheses

= 3 \cdot \frac{1}{3} + 3 \cdot \frac{2}{27} x^{2} + 3 \cdot \frac{2}{81} x^{3} - x \frac{1}{3} - x \frac{2}{27} x^{2} - x \frac{2}{81} x^{3}

Simplify

3 \cdot \frac{1}{3} + 3 \cdot \frac{2}{27} x^{2} + 3 \cdot \frac{2}{81} x^{3} - x \frac{1}{3} - x \frac{2}{27} x^{2} - x \frac{2}{81} x^{3} : 1 + \frac{2 x ^{2}}{9} - \frac{x}{3} - \frac{2 x ^{4}}{81}

= 1 + \frac{2 x ^{2}}{9} - \frac{x}{3} - \frac{2 x ^{4}}{81}

\frac{2 ( 6 + 5 )}{3}

(x^{2} - 2)^{2} 1 + x

P (- 1, 2) Q (4, - 5)

\frac{1 + x ^{2}}{1 + x}

(2 x - \frac{1}{2} y)^{5}

What is expand (3-x)(1/3+2/27 x^2+2/81 x^3) ?
The solution to expand (3-x)(1/3+2/27 x^2+2/81 x^3) is 1+(2x^2)/9-x/3-(2x^4)/(81)