What is ((2+j)(0.6+j^{0.8}))/(-4+j)-j ?

The solution to ((2+j)(0.6+j^{0.8}))/(-4+j)-j is (-j^2+j^{1.8}+2j^{0.8}+4.6j+1.2)/(-4+j)

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simplify ((2+j)(0.6+j^{0.8}))/(-4+j)-j

simplify

\frac{( 2 + j ) ( 0.6 + j ^{0.8} )}{- 4 + j} - j

\frac{- j ^{2} + j ^{1.8} + 2 j ^{0.8} + 4.6 j + 1.2}{- 4 + j}

Solution steps

\frac{( 2 + j ) ( 0.6 + j ^{0.8} )}{- 4 + j} - j

Apply the fraction rule:

a + \frac{b}{c} = \frac{a c + b}{c}

= \frac{- j ( - 4 + j ) + ( 2 + j ) ( 0.6 + j ^{0.8} )}{- 4 + j}

Simplify

- j (- 4 + j) + (2 + j) (0.6 + j^{0.8}) : - j^{2} + j^{1.8} + 2 j^{0.8} + 4.6 j + 1.2

= \frac{- j ^{2} + j ^{1.8} + 2 j ^{0.8} + 4.6 j + 1.2}{- 4 + j}

lo g_{10} (3) (4 x + 6) - lo g_{3} (3 x + 9)

\frac{1}{4} (- 16 x + 8)

440

\frac{x + 1}{( x + 7 ) ^{2}}

lo g_{10} (x y^{7})

What is ((2+j)(0.6+j^{0.8}))/(-4+j)-j ?
The solution to ((2+j)(0.6+j^{0.8}))/(-4+j)-j is (-j^2+j^{1.8}+2j^{0.8}+4.6j+1.2)/(-4+j)