What is (\partial)/(\partial x)((z)(x+y+z)) ?

The answer to (\partial)/(\partial x)((z)(x+y+z)) is z

Popular >

(\partial)/(\partial x)((z)(x+y+z))

\frac{\partial}{\partial x} ((z) (x + y + z))

z

Solution steps

\frac{\partial}{\partial x} ((z) (x + y + z))

Treat

z, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z \frac{\partial}{\partial x} (x + y + z)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= z (\frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y) + \frac{\partial}{\partial x} (z))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (z) = 0

= z (1 + 0 + 0)

Simplify

= z

v (- 5 - 1) f (3.1)

2 (1 - x) sin^{2} (1 - x)

(cos (π t), 2 e^{t} + 5) (- π sin (π t), e^{t})

\frac{K}{j w ( j w + 3 ) ( j w + 5 )}

\frac{( M - d ) ^{2}}{8 d}

What is (\partial)/(\partial x)((z)(x+y+z)) ?
The answer to (\partial)/(\partial x)((z)(x+y+z)) is z