What is expand (dx)/d (x^4-8x^2+7=0) ?

The solution to expand (dx)/d (x^4-8x^2+7=0) is (x^4dx)/d-(8x^2dx)/d+(7dx)/d =0

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expand (dx)/d (x^4-8x^2+7=0)

expand

\frac{d x}{d} (x^{4} - 8 x^{2} + 7 = 0)

\frac{x ^{4} d x}{d} - \frac{8 x ^{2} d x}{d} + \frac{7 d x}{d} = 0

Solution steps

\frac{d x}{d} (x^{4} - 8 x^{2} + 7 = 0)

= \frac{d x}{d} (x^{4} - 8 x^{2} + 7 \cdot 0 =)

Distribute parentheses

\frac{d x}{d} x^{4} + \frac{d x}{d} (- 8 x^{2}) + \frac{d x}{d} \cdot 7 = 0

Apply minus-plus rules

+ (- a) = - a

\frac{d x}{d} x^{4} - 8 \cdot \frac{d x}{d} x^{2} + 7 \cdot \frac{d x}{d} = 0

Expand

\frac{d x}{d} x^{4} - 8 \cdot \frac{d x}{d} x^{2} + 7 \cdot \frac{d x}{d} : \frac{x ^{4} d x}{d} - \frac{8 x ^{2} d x}{d} + \frac{7 d x}{d}

\frac{x ^{4} d x}{d} - \frac{8 x ^{2} d x}{d} + \frac{7 d x}{d} = 0

c (- 2 e^{- 2 x} x + e^{- 2 x})

(3 i - 2 j + k) 2 (- 5 i - j + 7 k)

\frac{( e + 1 ) ( e - 1 )}{1 + e ^{2}}

(x^{\frac{5}{2}} - y^{\frac{1}{4}}) (x^{\frac{5}{2}} + y^{\frac{1}{4}})

(2 x + y) d x

What is expand (dx)/d (x^4-8x^2+7=0) ?
The solution to expand (dx)/d (x^4-8x^2+7=0) is (x^4dx)/d-(8x^2dx)/d+(7dx)/d =0