What is expand A(-3,-2)B(1,-2)C(1,2) ?

The solution to expand A(-3,-2)B(1,-2)C(1,2) is -3(1*2,)ABC,1,3,2-2*1*(1*2,)ABC,2*2

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expand A(-3,-2)B(1,-2)C(1,2)

expand

A (- 3, - 2) B (1, - 2) C (1, 2)

- 3 (1 \cdot 2,) A BC, 1, 3, 2 - 2 \cdot 1 \cdot (1 \cdot 2,) A BC, 2 \cdot 2

Solution steps

A (- 3, - 2) B (1, - 2) C (1, 2)

= (- 3, - 2) (1, - 2) (1 \cdot 2,) A BC

Expand

(- 3, - 2) (1, - 2) : - 3, 1, 3, 2 - 2 \cdot 1, 2 \cdot 2

= A BC (1, 2) (- 3, 1, 3, 2 - 2 \cdot 1, 2 \cdot 2)

Expand

A BC (1, 2) (- 3, 1, 3, 2 - 2 \cdot 1, 2 \cdot 2) : - 3 (1 \cdot 2,) A BC, 1, 3, 2 - 2 \cdot 1 \cdot (1 \cdot 2,) A BC, 2 \cdot 2

= - 3 (1 \cdot 2,) A BC, 1, 3, 2 - 2 \cdot 1 \cdot (1 \cdot 2,) A BC, 2 \cdot 2

4 a (a + a)

(x^{3} - 3 x y)^{2} + (3 x^{2} y - y^{3})^{2}

(1 - \frac{1}{z}) (1 - \frac{0.2}{z})

\frac{( s ^{2} + s + 1 )}{( s ^{2} + 1 ) ( s + 2 ) ( s + 4 )}

- \frac{0.05}{x ( 0.056 + x )}

What is expand A(-3,-2)B(1,-2)C(1,2) ?
The solution to expand A(-3,-2)B(1,-2)C(1,2) is -3(1*2,)ABC,1,3,2-2*1*(1*2,)ABC,2*2