What is expand (-2cos(2x)-2sin(2x))^2 ?

The solution to expand (-2cos(2x)-2sin(2x))^2 is 4sin(4x)+4

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expand (-2cos(2x)-2sin(2x))^2

expand

(- 2 cos (2 x) - 2 sin (2 x))^{2}

4 sin (4 x) + 4

Solution steps

(- 2 cos (2 x) - 2 sin (2 x))^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(- 2 cos (2 x) - 2 sin (2 x))^{2} = (- 2 cos (2 x))^{2} - 2 (- 2 cos (2 x)) \cdot 2 sin (2 x) + (2 sin (2 x))^{2}

= (- 2 cos (2 x))^{2} - 2 (- 2 cos (2 x)) \cdot 2 sin (2 x) + (2 sin (2 x))^{2}

Simplify

(- 2 cos (2 x))^{2} - 2 (- 2 cos (2 x)) \cdot 2 sin (2 x) + (2 sin (2 x))^{2} : 4 (sin (4 x) + 1)

= 4 (sin (4 x) + 1)

Apply the distributive law:

a (b + c) = ab + a c

4 (sin (4 x) + 1) = 4 sin (4 x) + 4 \cdot 1

= 4 sin (4 x) + 4 \cdot 1

Multiply the numbers:

4 \cdot 1 = 4

= 4 sin (4 x) + 4

e^{z^{2} - (1 + i) z + 3} (2 z - 1 - i)

(- 5, - 7) y (5, 0)

in (x^{6} y^{3})

\frac{1 + e ^{t}}{e ^{t} ( t + 1 )}

(x + sin (y) - cos (y)) d x + (sin (y) + cos (y))

What is expand (-2cos(2x)-2sin(2x))^2 ?
The solution to expand (-2cos(2x)-2sin(2x))^2 is 4sin(4x)+4