What is expand (x-2)(x+1)(x-3i)(x+3i) ?

The solution to expand (x-2)(x+1)(x-3i)(x+3i) is x^4-x^3+7x^2-9x-18

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expand (x-2)(x+1)(x-3i)(x+3i)

expand

(x - 2) (x + 1) (x - 3 i) (x + 3 i)

x^{4} - x^{3} + 7 x^{2} - 9 x - 18

Solution steps

(x - 2) (x + 1) (x - 3 i) (x + 3 i)

Expand

(x - 2) (x + 1) (x - 3 i) (x + 3 i) : (x - 2) (x + 1) (x^{2} + 9)

= (x - 2) (x + 1) (x^{2} + 9)

Apply FOIL method

(x - 2) (x + 1) : x^{2} - x - 2

= (x^{2} - x - 2) (x^{2} + 9)

Distribute parentheses

= x^{2} x^{2} + x^{2} \cdot 9 - x x^{2} - x \cdot 9 - 2 x^{2} - 2 \cdot 9

Simplify

x^{2} x^{2} + x^{2} \cdot 9 - x x^{2} - x \cdot 9 - 2 x^{2} - 2 \cdot 9 : x^{4} - x^{3} + 7 x^{2} - 9 x - 18

= x^{4} - x^{3} + 7 x^{2} - 9 x - 18

(x + 25) (x - 25) (x + 3)

(1 + \frac{1}{4} y)^{6}

(x^{2} - 1) y^{3} d x + x^{2} d y

(s + 4 - 7 i)^{2}

\frac{1}{( 7 - 5 \cdot i \cdot x ) ^{7}}

What is expand (x-2)(x+1)(x-3i)(x+3i) ?
The solution to expand (x-2)(x+1)(x-3i)(x+3i) is x^4-x^3+7x^2-9x-18