What is expand (pgsin(θ)(-y^2+2L^2y))/(2Lm) ?

The solution to expand (pgsin(θ)(-y^2+2L^2y))/(2Lm) is -(pgy^2sin(θ)}{2Lm}+\frac{pLgysin(θ))/m

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expand (pgsin(θ)(-y^2+2L^2y))/(2Lm)

expand

\frac{p g sin ( θ ) ( - y ^{2} + 2 L ^{2} y )}{2 L m}

- \frac{p g y ^{2} sin ( θ )}{2 L m} + \frac{p Lg y sin ( θ )}{m}

Solution steps

\frac{p g sin ( θ ) ( - y ^{2} + 2 L ^{2} y )}{2 L m}

Expand

p g sin (θ) (- y^{2} + 2 L^{2} y) : - p g y^{2} sin (θ) + 2 p L^{2} g y sin (θ)

= \frac{- p g y ^{2} sin ( θ ) + 2 p L ^{2} g y sin ( θ )}{2 L m}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- p g y ^{2} sin ( θ ) + 2 p L ^{2} g y sin ( θ )}{2 L m} = - \frac{p g y ^{2} sin ( θ )}{2 L m} + \frac{2 p L ^{2} g y sin ( θ )}{2 L m}

= - \frac{p g y ^{2} sin ( θ )}{2 L m} + \frac{2 p L ^{2} g y sin ( θ )}{2 L m}

Cancel

\frac{2 p L ^{2} g y sin ( θ )}{2 L m} : \frac{p Lg y sin ( θ )}{m}

= - \frac{p g y ^{2} sin ( θ )}{2 L m} + \frac{p Lg y sin ( θ )}{m}

\frac{x ^{2} + 2 s + 53}{( s ^{2} + 49 ) \cdot ( s + 2 )}

\frac{π ( 17 17 - 5 5 )}{6}

(7 - t + 2)^{2}

\frac{4 ( 3 3 - π )}{3}

\frac{d ^{2}}{d t ^{2}} ((x) (8 - 4 t + t^{2}))

What is expand (pgsin(θ)(-y^2+2L^2y))/(2Lm) ?
The solution to expand (pgsin(θ)(-y^2+2L^2y))/(2Lm) is -(pgy^2sin(θ)}{2Lm}+\frac{pLgysin(θ))/m