What is expand (6(2N^2+3N+1))/(N^2) ?

The solution to expand (6(2N^2+3N+1))/(N^2) is 12+(18)/N+6/(N^2)

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expand (6(2N^2+3N+1))/(N^2)

expand

\frac{6 ( 2 N ^{2} + 3 N + 1 )}{N ^{2}}

12 + \frac{18}{N} + \frac{6}{N ^{2}}

Solution steps

\frac{6 ( 2 N ^{2} + 3 N + 1 )}{N ^{2}}

Expand

6 (2 N^{2} + 3 N + 1) : 12 N^{2} + 18 N + 6

= \frac{12 N ^{2} + 18 N + 6}{N ^{2}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{12 N ^{2} + 18 N + 6}{N ^{2}} = \frac{12 N ^{2}}{N ^{2}} + \frac{18 N}{N ^{2}} + \frac{6}{N ^{2}}

= \frac{12 N ^{2}}{N ^{2}} + \frac{18 N}{N ^{2}} + \frac{6}{N ^{2}}

Cancel

\frac{12 N ^{2}}{N ^{2}} : 12

= 12 + \frac{18 N}{N ^{2}} + \frac{6}{N ^{2}}

Cancel

\frac{18 N}{N ^{2}} : \frac{18}{N}

= 12 + \frac{18}{N} + \frac{6}{N ^{2}}

4 \cdot (a \cdot (2 + 2^{t} + 3^{t}))

(1 + 3 j) (1 - 3 j)

\frac{( x - 1 ) ( x - 2.5 )}{( x - 3 )} - 1

(ni + 2)^{2}

\frac{2 ( x - 3 ) \cdot e ^{8 x}}{( x + 5 ) ^{7}}

What is expand (6(2N^2+3N+1))/(N^2) ?
The solution to expand (6(2N^2+3N+1))/(N^2) is 12+(18)/N+6/(N^2)