What is ((2n)/7-2x^2)*3y^4 ?

The solution to ((2n)/7-2x^2)*3y^4 is (3y^4(-14x^2+2n))/7

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simplify ((2n)/7-2x^2)*3y^4

simplify

(\frac{2 n}{7} - 2 x^{2}) \cdot 3 y^{4}

\frac{3 y ^{4} ( - 14 x ^{2} + 2 n )}{7}

Solution steps

(\frac{2 n}{7} - 2 x^{2}) \cdot 3 y^{4}

Join

\frac{2 n}{7} - 2 x^{2} : \frac{- 14 x ^{2} + 2 n}{7}

= \frac{- 14 x ^{2} + 2 n}{7} \cdot 3 y^{4}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - 14 x ^{2} + 2 n ) \cdot 3 y ^{4}}{7}

= \frac{3 ( - 14 x ^{2} + 2 n ) y ^{4}}{7}

= \frac{3 y ^{4} ( - 14 x ^{2} + 2 n )}{7}

(x^{3} - \frac{1}{x ^{2}})^{3}

\frac{3}{2 ( x - 2 ) ^{2}}

, (2 t^{2} - 1) 2 d t

(- 3 - 5 i)^{6}

\frac{x ^{5} + 2 x ^{3} - 2 x ^{2} - 2 x - 24}{( x - 1 ) ^{2} ( x ^{2} + 4 ) ^{2}}

What is ((2n)/7-2x^2)*3y^4 ?
The solution to ((2n)/7-2x^2)*3y^4 is (3y^4(-14x^2+2n))/7