What is expand (5x^2+5)(2x+1) ?

The solution to expand (5x^2+5)(2x+1) is 2x(5x^2+5)+(5x^2+5)

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expand (5x^2+5)(2x+1)

expand

(5 x^{2} + 5)^{\circ} (2 x + 1)

2 x (5 x^{2} + 5)^{\circ} + (5 x^{2} + 5)^{\circ}

Solution steps

(5 x^{2} + 5)^{\circ} (2 x + 1)

= (2 x + 1) (5 x^{2} + 5)^{\circ}

Apply the distributive law:

a (b + c) = ab + a c

a = (5 x^{2} + 5)^{\circ}, b = 2 x, c = 1

= (5 x^{2} + 5)^{\circ} \cdot 2 x + (5 x^{2} + 5)^{\circ} \cdot 1

= 2 x (5 x^{2} + 5)^{\circ} + 1 \cdot (5 x^{2} + 5)^{\circ}

Multiply:

1 \cdot (5 x^{2} + 5)^{\circ} = (5 x^{2} + 5)^{\circ}

= 2 x (5 x^{2} + 5)^{\circ} + (5 x^{2} + 5)^{\circ}

(A e^{im θ} + B e^{- im θ})^{2}

\frac{1}{4 ( 8 - a - b - y ) ^{2}}

a sin (\frac{π}{4} (k + 1)) + b cos (\frac{π}{4} (k + 1))

- 3 (8 e^{- 3 x} - 2 cos (2 x) + 3 sin (2 x)) + 13 sin (2 t)

\frac{( 2 x - 7 ) ( x + 1 )}{x + 5}

What is expand (5x^2+5)(2x+1) ?
The solution to expand (5x^2+5)(2x+1) is 2x(5x^2+5)+(5x^2+5)