What is expand dx(1/15 arctan(x/5)+c) ?

The solution to expand dx(1/15 arctan(x/5)+c) is (arctan(x/5)dx)/(15)+cdx

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expand dx(1/15 arctan(x/5)+c)

expand

d x (\frac{1}{15} arctan (\frac{x}{5}) + c)

\frac{arctan ( \frac{x}{5} ) d x}{15} + c d x

Solution steps

d x (\frac{1}{15} arctan (\frac{x}{5}) + c)

Apply the distributive law:

a (b + c) = ab + a c

a = d x, b = \frac{1}{15} arctan (\frac{x}{5}), c = c

= d x \frac{1}{15} arctan (\frac{x}{5}) + d x c

= \frac{1}{15} arctan (\frac{x}{5}) d x + c d x

Simplify

\frac{1}{15} arctan (\frac{x}{5}) d x + c d x : \frac{arctan ( \frac{x}{5} ) d x}{15} + c d x

= \frac{arctan ( \frac{x}{5} ) d x}{15} + c d x

\frac{3 ( x - 5 )}{2 ( x ^{2} + 5 - 2 s )}

(16 - x^{2} - 3)^{2}

\frac{( x ^{5} - 2 \cdot x ^{3} - 3 \cdot x ) ^{2} - 1}{( x ^{4} - 3 \cdot x ^{2} + 1 )}

- 6 (b - 7 = - 66)

(cos (2 x))^{2}

What is expand dx(1/15 arctan(x/5)+c) ?
The solution to expand dx(1/15 arctan(x/5)+c) is (arctan(x/5)dx)/(15)+cdx