What is expand (7x(x+2))/(3y^2(2x+1)) ?

The solution to expand (7x(x+2))/(3y^2(2x+1)) is (7x^2+14x)/(6xy^2+3y^2)

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expand (7x(x+2))/(3y^2(2x+1))

expand

\frac{7 x ( x + 2 )}{3 y ^{2} ( 2 x + 1 )}

\frac{7 x ^{2} + 14 x}{6 x y ^{2} + 3 y ^{2}}

Solution steps

\frac{7 x ( x + 2 )}{3 y ^{2} ( 2 x + 1 )}

Expand

3 y^{2} (2 x + 1) : 6 x y^{2} + 3 y^{2}

= \frac{7 x ( x + 2 )}{6 x y ^{2} + 3 y ^{2}}

Expand

7 x (x + 2) : 7 x^{2} + 14 x

= \frac{7 x ^{2} + 14 x}{6 x y ^{2} + 3 y ^{2}}

2 l e f t (3 c + 5) - 4 c

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(i + 3)^{4}

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\frac{d}{d x} ((t) (a (x - h)^{2} + k))

What is expand (7x(x+2))/(3y^2(2x+1)) ?
The solution to expand (7x(x+2))/(3y^2(2x+1)) is (7x^2+14x)/(6xy^2+3y^2)