What is expand-3(x+Δx)^2 ?

The solution to expand-3(x+Δx)^2 is -3x^2-6Δx^2-3Δ^2x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand-3(x+Δx)^2

expand

- 3 (x + Δ x)^{2}

- 3 x^{2} - 6Δ x^{2} - 3 Δ^{2} x^{2}

Solution steps

- 3 (x + Δ x)^{2}

(x + Δ x)^{2} = x^{2} + 2Δ x^{2} + Δ^{2} x^{2}

= - 3 (x^{2} + 2Δ x^{2} + Δ^{2} x^{2})

Distribute parentheses

= (- 3) x^{2} + (- 3) \cdot 2Δ x^{2} + (- 3) Δ^{2} x^{2}

Apply minus-plus rules

+ (- a) = - a

= - 3 x^{2} - 3 \cdot 2Δ x^{2} - 3 Δ^{2} x^{2}

Multiply the numbers:

3 \cdot 2 = 6

= - 3 x^{2} - 6Δ x^{2} - 3 Δ^{2} x^{2}

(i + 3)^{5}

\frac{sin ( θ )}{\frac{d}{d θ} ( ( θ x ( θ ) ) ( θ - sin ( θ ) ) )}

\frac{8 π}{( w - π ) ^{2}}

\frac{8 x - 5}{3 ( 5 x + 8 ) ^{\frac{4}{3}} ( x ^{2} + 1 ) ^{\frac{5}{6}}}

(x - 4 x + 5) \cdot (x + 4 x + 5)

What is expand-3(x+Δx)^2 ?
The solution to expand-3(x+Δx)^2 is -3x^2-6Δx^2-3Δ^2x^2