What is (s-5/3+2k)(s+5/3+j) ?

The solution to (s-5/3+2k)(s+5/3+j) is ((3s-5+6k)(3s+5+3j))/9

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simplify (s-5/3+2k)(s+5/3+j)

simplify

(s - \frac{5}{3} + 2 k) (s + \frac{5}{3} + j)

\frac{( 3 s - 5 + 6 k ) ( 3 s + 5 + 3 j )}{9}

Solution steps

(s - \frac{5}{3} + 2 k) (s + \frac{5}{3} + j)

Simplify

s - \frac{5}{3} + 2 k : \frac{3 s - 5 + 6 k}{3}

= \frac{3 s - 5 + 6 k}{3} (s + \frac{5}{3} + j)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 3 s - 5 + 6 k ) ( s + \frac{5}{3} + j )}{3}

Simplify

(3 s - 5 + 6 k) (s + \frac{5}{3} + j) : \frac{( 3 s - 5 + 6 k ) ( s \cdot 3 + 5 + j \cdot 3 )}{3}

= \frac{\frac{( 3 s - 5 + 6 k ) ( s \cdot 3 + 5 + j \cdot 3 )}{3}}{3}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 3 s - 5 + 6 k ) ( s \cdot 3 + 5 + j \cdot 3 )}{3 \cdot 3}

Multiply the numbers:

3 \cdot 3 = 9

= \frac{( 3 s - 5 + 6 k ) ( s \cdot 3 + 5 + j \cdot 3 )}{9}

= \frac{( 3 s - 5 + 6 k ) ( 3 s + 5 + 3 j )}{9}

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What is (s-5/3+2k)(s+5/3+j) ?
The solution to (s-5/3+2k)(s+5/3+j) is ((3s-5+6k)(3s+5+3j))/9