What is expand ((4-x)^3)/(64) ?

The solution to expand ((4-x)^3)/(64) is -(x^3}{64}+(3x^2)/(16)-\frac{3x)/4+1

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expand ((4-x)^3)/(64)

expand

\frac{( 4 - x ) ^{3}}{64}

- \frac{x ^{3}}{64} + \frac{3 x ^{2}}{16} - \frac{3 x}{4} + 1

Solution steps

\frac{( 4 - x ) ^{3}}{64}

(4 - x)^{3} = 64 - 48 x + 12 x^{2} - x^{3}

= \frac{64 - 48 x + 12 x ^{2} - x ^{3}}{64}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{64 - 48 x + 12 x ^{2} - x ^{3}}{64} = \frac{64}{64} - \frac{48 x}{64} + \frac{12 x ^{2}}{64} - \frac{x ^{3}}{64}

= \frac{64}{64} - \frac{48 x}{64} + \frac{12 x ^{2}}{64} - \frac{x ^{3}}{64}

Apply rule

\frac{a}{a} = 1

\frac{64}{64} = 1

= 1 - \frac{48 x}{64} + \frac{12 x ^{2}}{64} - \frac{x ^{3}}{64}

Cancel

\frac{48 x}{64} : \frac{3 x}{4}

= 1 - \frac{3 x}{4} + \frac{12 x ^{2}}{64} - \frac{x ^{3}}{64}

Cancel

\frac{12 x ^{2}}{64} : \frac{3 x ^{2}}{16}

= 1 - \frac{3 x}{4} + \frac{3 x ^{2}}{16} - \frac{x ^{3}}{64}

Rewrite in standard form

= - \frac{x ^{3}}{64} + \frac{3 x ^{2}}{16} - \frac{3 x}{4} + 1

(- x^{(2)} + 3 x + 1) d x

\frac{5 x}{2 ( x - 3 )}

(2 n - 1) (2 n +!)

\frac{( u + 3 ) ( 5 u + 1 )}{10 u ^{2} - 11 u + 1}

(- 4 x + 1) (x - 5)

What is expand ((4-x)^3)/(64) ?
The solution to expand ((4-x)^3)/(64) is -(x^3}{64}+(3x^2)/(16)-\frac{3x)/4+1