What is expand (derivative of 1/(x+1)-1)/(in(2+x)) ?

The solution to expand (derivative of 1/(x+1)-1)/(in(2+x)) is (derivative of 1/(x+1)-1)/(2in+inx)

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expand (derivative of 1/(x+1)-1)/(in(2+x))

expand

\frac{\frac{d}{d x} ( \frac{1}{x + 1} ) - 1}{in ( 2 + x )}

\frac{\frac{d}{d x} ( \frac{1}{x + 1} ) - 1}{2 in + in x}

Solution steps

\frac{\frac{d}{d x} ( \frac{1}{x + 1} ) - 1}{in ( 2 + x )}

Expand

in (2 + x) : 2 in + in x

= \frac{\frac{d}{d x} ( \frac{1}{x + 1} ) - 1}{2 in + in x}

(x - 1 - 2 x - 3)^{2}

\frac{y ( 1 - x )}{x ( 2 y - 1 )}

[e^{(- 4 t)} U (t - 3)]

(cos (3 x) + 3)^{2}

What is expand (derivative of 1/(x+1)-1)/(in(2+x)) ?
The solution to expand (derivative of 1/(x+1)-1)/(in(2+x)) is (derivative of 1/(x+1)-1)/(2in+inx)