What is expand (20)/((x+3)(x-5)) ?

The solution to expand (20)/((x+3)(x-5)) is (20)/(x^2-2x-15)

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expand (20)/((x+3)(x-5))

expand

\frac{20}{( x + 3 ) ( x - 5 )}

\frac{20}{x ^{2} - 2 x - 15}

Solution steps

\frac{20}{( x + 3 ) ( x - 5 )}

Expand

(x + 3) (x - 5) : x^{2} - 2 x - 15

= \frac{20}{x ^{2} - 2 x - 15}

(e^{x}) (2 x + 1)

(3 + 5)^{4}

(3 + \frac{2 i}{n}) - (7 (3 + \frac{2 i}{n})^{2})

- u_{2} e^{t - 2} + u_{2} e^{2 (t - 2)}

\frac{( 4 x + 5 ) ( 2 x + 3 )}{2}

What is expand (20)/((x+3)(x-5)) ?
The solution to expand (20)/((x+3)(x-5)) is (20)/(x^2-2x-15)