What is expand 1/3 (x^2+3)^3 ?

The solution to expand 1/3 (x^2+3)^3 is (x^6)/3+3x^4+9x^2+9

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expand 1/3 (x^2+3)^3

expand

\frac{1}{3} (x^{2} + 3)^{3}

\frac{x ^{6}}{3} + 3 x^{4} + 9 x^{2} + 9

Solution steps

\frac{1}{3} (x^{2} + 3)^{3}

Expand

(x^{2} + 3)^{3} : x^{6} + 9 x^{4} + 27 x^{2} + 27

= \frac{1}{3} (x^{6} + 9 x^{4} + 27 x^{2} + 27)

Distribute parentheses

= \frac{1}{3} x^{6} + \frac{1}{3} \cdot 9 x^{4} + \frac{1}{3} \cdot 27 x^{2} + \frac{1}{3} \cdot 27

Simplify

\frac{1}{3} x^{6} + \frac{1}{3} \cdot 9 x^{4} + \frac{1}{3} \cdot 27 x^{2} + \frac{1}{3} \cdot 27 : \frac{x ^{6}}{3} + 3 x^{4} + 9 x^{2} + 9

= \frac{x ^{6}}{3} + 3 x^{4} + 9 x^{2} + 9

(0.12256 + 0.74486 i)^{4}

\frac{- z - 1}{8 ( z ^{2} + 1 )}

\frac{40 ( 230 + 23 )}{2299}

(5 - x)^{4} d x

(24 x^{\frac{1}{2}} - 10 x^{\frac{3}{2}}) d x

What is expand 1/3 (x^2+3)^3 ?
The solution to expand 1/3 (x^2+3)^3 is (x^6)/3+3x^4+9x^2+9