What is expand ((2x+3)^3)/3 ?

The solution to expand ((2x+3)^3)/3 is (8x^3)/3+12x^2+18x+9

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expand ((2x+3)^3)/3

expand

\frac{( 2 x + 3 ) ^{3}}{3}

\frac{8 x ^{3}}{3} + 12 x^{2} + 18 x + 9

Solution steps

\frac{( 2 x + 3 ) ^{3}}{3}

(2 x + 3)^{3} = 8 x^{3} + 36 x^{2} + 54 x + 27

= \frac{8 x ^{3} + 36 x ^{2} + 54 x + 27}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{8 x ^{3} + 36 x ^{2} + 54 x + 27}{3} = \frac{8 x ^{3}}{3} + \frac{36 x ^{2}}{3} + \frac{54 x}{3} + \frac{27}{3}

= \frac{8 x ^{3}}{3} + \frac{36 x ^{2}}{3} + \frac{54 x}{3} + \frac{27}{3}

Divide the numbers:

\frac{36}{3} = 12

= \frac{8 x ^{3}}{3} + 12 x^{2} + \frac{54 x}{3} + \frac{27}{3}

Divide the numbers:

\frac{54}{3} = 18

= \frac{8 x ^{3}}{3} + 12 x^{2} + 18 x + \frac{27}{3}

Divide the numbers:

\frac{27}{3} = 9

= \frac{8 x ^{3}}{3} + 12 x^{2} + 18 x + 9

- \frac{1}{t ( t - 1 ) ( s ^{2} + 2 s + 26 )}

(x y^{'} (x) - y)^{2}

2 a (\frac{1}{5} b + \frac{t}{2})

\frac{( 2 + 5 y ) ^{2}}{4}

(x + 1.5) \cdot (x + 0, 3) \cdot (x - 2, 7)

What is expand ((2x+3)^3)/3 ?
The solution to expand ((2x+3)^3)/3 is (8x^3)/3+12x^2+18x+9