What are the solutions to the equation x^2-12x+8=0 ?

The solutions to the equation x^2-12x+8=0 are x=2(3+sqrt(7)),x=2(3-sqrt(7))

Find the zeros of x^2-12x+8=0

The zeros of x^2-12x+8=0 are x=2(3+sqrt(7)),x=2(3-sqrt(7))

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x^{2} - 12 x + 8 = 0

x = 2 (3 + 7), x = 2 (3 - 7)

Decimal Notation

x = 11.29150 \dots, x = 0.70849 \dots

Solution steps

x^{2} - 12 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 8 = 47

x_{1, 2} = \frac{- ( - 12 ) \pm 4 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 7}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 4 7}{2 \cdot 1}

x = \frac{- ( - 12 ) + 4 7}{2 \cdot 1} : 2 (3 + 7)

x = \frac{- ( - 12 ) - 4 7}{2 \cdot 1} : 2 (3 - 7)

The solutions to the quadratic equation are:

x = 2 (3 + 7), x = 2 (3 - 7)

6 - \frac{9}{2}

25 y^{2} + 60 y + 36

- \frac{3}{4} + \frac{7}{8}

x + x

lo g_{\frac{1}{7}} (12 - x) \geq - 2

What are the solutions to the equation x^2-12x+8=0 ?
The solutions to the equation x^2-12x+8=0 are x=2(3+sqrt(7)),x=2(3-sqrt(7))
Find the zeros of x^2-12x+8=0
The zeros of x^2-12x+8=0 are x=2(3+sqrt(7)),x=2(3-sqrt(7))