What is expand (x+2)sin(x^2+4x+17) ?

The solution to expand (x+2)sin(x^2+4x+17) is xsin(x^2+4x+17)+2sin(x^2+4x+17)

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expand (x+2)sin(x^2+4x+17)

expand

(x + 2) sin (x^{2} + 4 x + 17)

x sin (x^{2} + 4 x + 17) + 2 sin (x^{2} + 4 x + 17)

Solution steps

(x + 2) sin (x^{2} + 4 x + 17)

= sin (x^{2} + 4 x + 17) (x + 2)

Apply the distributive law:

a (b + c) = ab + a c

sin (x^{2} + 4 x + 17) (x + 2) = sin (x^{2} + 4 x + 17) x + sin (x^{2} + 4 x + 17) \cdot 2

= sin (x^{2} + 4 x + 17) x + sin (x^{2} + 4 x + 17) \cdot 2

= x sin (x^{2} + 4 x + 17) + 2 sin (x^{2} + 4 x + 17)

(1 - 2 cos (x) + cos (2 x))^{2}

(tan^{(2)} (y) - cot^{(2)} (y))^{(2)}

\frac{2 ( 30 + 7 )}{3}

163 π + \frac{π ( 165 - 8 2 )}{6}

\frac{- 3 x + 25}{( x - 5 ) ( x + 5 )}

What is expand (x+2)sin(x^2+4x+17) ?
The solution to expand (x+2)sin(x^2+4x+17) is xsin(x^2+4x+17)+2sin(x^2+4x+17)