What is sqrt(2u^2+2v^2+4)((u^2+v^2)) ?

The solution to sqrt(2u^2+2v^2+4)((u^2+v^2)) is (u^2+v^2)sqrt(2u^2+2v^2+4)

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simplify sqrt(2u^2+2v^2+4)((u^2+v^2))

simplify

2 u^{2} + 2 v^{2} + 4 ((u^{2} + v^{2}))

(u^{2} + v^{2}) 2 u^{2} + 2 v^{2} + 4

Solution steps

2 u^{2} + 2 v^{2} + 4 ((u^{2} + v^{2}))

Apply rule:

(a) = a

((u^{2} + v^{2})) = (u^{2} + v^{2})

= 2 u^{2} + 2 v^{2} + 4 (u^{2} + v^{2})

= (u^{2} + v^{2}) 2 u^{2} + 2 v^{2} + 4

(2 m - 3 b) e^{3}

(12 t - 13 e^{3 t} + 4)^{2}

x^{\frac{1}{2}} \cdot (x^{2} + 1)

\frac{( x - 1 ) ( x ^{2} + x + 1 )}{x ^{2} + 1}

\frac{( z ( 1 + 2 z ^{2} ) )}{( ( - 2 + z ) ^{2} ( - 1 + z ) )}

What is sqrt(2u^2+2v^2+4)((u^2+v^2)) ?
The solution to sqrt(2u^2+2v^2+4)((u^2+v^2)) is (u^2+v^2)sqrt(2u^2+2v^2+4)