What is expand {(e^{3t}+e^{-3t})cos(t)}s ?

The solution to expand {(e^{3t}+e^{-3t})cos(t)}s is e^{3t}scos(t)+e^{-3t}scos(t)

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expand {(e^{3t}+e^{-3t})cos(t)}s

expand

{(e^{3 t} + e^{- 3 t}) cos (t)} s

e^{3 t} s cos (t) + e^{- 3 t} s cos (t)

Solution steps

((e^{3 t} + e^{- 3 t}) cos (t)) s

Remove parentheses:

(a) = a

= (e^{3 t} + e^{- 3 t}) cos (t) s

= s cos (t) (e^{3 t} + e^{- 3 t})

Apply the distributive law:

a (b + c) = ab + a c

a = cos (t) s, b = e^{3 t}, c = e^{- 3 t}

= cos (t) s e^{3 t} + cos (t) s e^{- 3 t}

= e^{3 t} s cos (t) + e^{- 3 t} s cos (t)

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What is expand {(e^{3t}+e^{-3t})cos(t)}s ?
The solution to expand {(e^{3t}+e^{-3t})cos(t)}s is e^{3t}scos(t)+e^{-3t}scos(t)