What is (x/2+3/4)(x/2-8/9) ?

The solution to (x/2+3/4)(x/2-8/9) is ((2x+3)(9x-16))/(72)

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simplify (x/2+3/4)(x/2-8/9)

simplify

(\frac{x}{2} + \frac{3}{4}) (\frac{x}{2} - \frac{8}{9})

\frac{( 2 x + 3 ) ( 9 x - 16 )}{72}

Solution steps

(\frac{x}{2} + \frac{3}{4}) (\frac{x}{2} - \frac{8}{9})

Simplify

\frac{x}{2} + \frac{3}{4} : \frac{2 x + 3}{4}

= \frac{2 x + 3}{4} (\frac{x}{2} - \frac{8}{9})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 2 x + 3 ) ( \frac{x}{2} - \frac{8}{9} )}{4}

Simplify

(2 x + 3) (\frac{x}{2} - \frac{8}{9}) : \frac{( 2 x + 3 ) ( x \cdot 9 - 16 )}{18}

= \frac{\frac{( 2 x + 3 ) ( x \cdot 9 - 16 )}{18}}{4}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 2 x + 3 ) ( x \cdot 9 - 16 )}{18 \cdot 4}

Multiply the numbers:

18 \cdot 4 = 72

= \frac{( 2 x + 3 ) ( x \cdot 9 - 16 )}{72}

= \frac{( 2 x + 3 ) ( 9 x - 16 )}{72}

\frac{1}{2} (ln ∣ e^{y} - 2 ∣ - y - x^{3})

x^{2} (2 x - \frac{4 x ^{3}}{3} + \frac{4 x ^{5}}{15})

1 - (\frac{x ^{2} - y ^{2}}{x ^{2} + y ^{2}})^{2}

(\frac{4}{3} + \frac{11 x}{3})^{3}

(x - a)^{2}

What is (x/2+3/4)(x/2-8/9) ?
The solution to (x/2+3/4)(x/2-8/9) is ((2x+3)(9x-16))/(72)