What is expand (x-3)(x-3-2i)(x+3-2i) ?

The solution to expand (x-3)(x-3-2i)(x+3-2i) is (x^3-3x^2-13x+39)+(12x-4x^2)i

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expand (x-3)(x-3-2i)(x+3-2i)

expand

(x - 3) (x - 3 - 2 i) (x + 3 - 2 i)

(x^{3} - 3 x^{2} - 13 x + 39) + (12 x - 4 x^{2}) i

Solution steps

(x - 3) (x - 3 - 2 i) (x + 3 - 2 i)

Expand

(x - 3) (x - 3 - 2 i) : 6 i + x^{2} - 6 x - 2 x i + 9

= (6 i + x^{2} - 6 x - 2 x i + 9) (x + 3 - 2 i)

Distribute parentheses

= 6 i x + 6 i 3 + 6 i (- 2 i) + x^{2} x + x^{2} \cdot 3 + x^{2} (- 2 i) - 6 xx - 6 x \cdot 3 - 6 x (- 2 i) - 2 x i x - 2 x i 3 - 2 x i (- 2 i) + 9 x + 9 \cdot 3 + 9 (- 2 i)

Simplify

6 i x + 6 i 3 + 6 i (- 2 i) + x^{2} x + x^{2} \cdot 3 + x^{2} (- 2 i) - 6 xx - 6 x \cdot 3 - 6 x (- 2 i) - 2 x i x - 2 x i 3 - 2 x i (- 2 i) + 9 x + 9 \cdot 3 + 9 (- 2 i) : x^{3} - 3 x^{2} + 12 x i - 4 x^{2} i - 13 x + 39

= x^{3} - 3 x^{2} + 12 x i - 4 x^{2} i - 13 x + 39

Rewrite in standard complex form:

(x^{3} - 3 x^{2} - 13 x + 39) + (12 x - 4 x^{2}) i

= (x^{3} - 3 x^{2} - 13 x + 39) + (12 x - 4 x^{2}) i

\frac{75 ( x - 8 ) ^{2}}{2}

\frac{x ^{4} + x ^{2} + 16 x - 12}{x ^{3} ( x - 2 ) ^{2}}

(\frac{2.6}{4} x^{π} + \frac{2.2}{6.8} y^{e})^{16}

x (x + 7) 11 d x

4 e^{x} (x^{2} - 49)

What is expand (x-3)(x-3-2i)(x+3-2i) ?
The solution to expand (x-3)(x-3-2i)(x+3-2i) is (x^3-3x^2-13x+39)+(12x-4x^2)i