What is expand 1/((x^2+9)(x-1)) ?

The solution to expand 1/((x^2+9)(x-1)) is 1/(x^3-x^2+9x-9)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 1/((x^2+9)(x-1))

expand

\frac{1}{( x ^{2} + 9 ) ( x - 1 )}

\frac{1}{x ^{3} - x ^{2} + 9 x - 9}

Solution steps

\frac{1}{( x ^{2} + 9 ) ( x - 1 )}

Expand

(x^{2} + 9) (x - 1) : x^{3} - x^{2} + 9 x - 9

= \frac{1}{x ^{3} - x ^{2} + 9 x - 9}

\frac{sin ( π z ^{2} ) + cos ( π z ^{2} )}{( z - 1 ) ( z - 2 )}

(4 cos (t) + 2 sin (t)) (- 2 sin (t) - 3 cos (t))

\frac{( x + 1 ) ^{2}}{x}

π (- \frac{2624 2}{21} - 48)

\frac{2 X ^{3}}{( X ^{2} + 1 ) ^{2}}

What is expand 1/((x^2+9)(x-1)) ?
The solution to expand 1/((x^2+9)(x-1)) is 1/(x^3-x^2+9x-9)