What are the solutions to the equation a^2+4a+4=0 ?

The solutions to the equation a^2+4a+4=0 are a=-2

Find the zeros of a^2+4a+4=0

The zeros of a^2+4a+4=0 are a=-2

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a^{2} + 4 a + 4 = 0

a = - 2

Solution steps

a^{2} + 4 a + 4 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

a_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

a = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

a = - 2

The solution to the quadratic equation is:

a = - 2

\frac{8 !}{7 ! ( 8 - 7 ) !}

∣ 5 - 3 x ∣ = 3

(\frac{- 2 x}{1 - x ^{2}})^{2}

\frac{2 π}{120 π}

- 27 = 2 x^{2} + 3 x

What are the solutions to the equation a^2+4a+4=0 ?
The solutions to the equation a^2+4a+4=0 are a=-2
Find the zeros of a^2+4a+4=0
The zeros of a^2+4a+4=0 are a=-2