What is expand (2/3 x+2y=0,)(3/4 x-5y=8) ?

The solution to expand (2/3 x+2y=0,)(3/4 x-5y=8) is (x^2)/2-(10xy)/3 =8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2/3 x+2y=0,)(3/4 x-5y=8)

expand

(\frac{2}{3} x + 2 y = 0,) (\frac{3}{4} x - 5 y = 8)

\frac{x ^{2}}{2} - \frac{10 x y}{3} = 8

Solution steps

(\frac{2}{3} x + 2 y = 0,) (\frac{3}{4} x - 5 y = 8)

= (\frac{2}{3} x + 2 \cdot 0 =, y) (\frac{3}{4} x - 5 \cdot 8 = y)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = \frac{2}{3} x, b = 2 y = 0,, c = \frac{3}{4} x, d = - 5 y = 8

\frac{2}{3} x \frac{3}{4} x + \frac{2}{3} x (- 5 y = 8) + 2 y = 0, \frac{3}{4} x + 2 y = 0, (- 5 y = 8)

Apply minus-plus rules

+ (- a) = - a

\frac{2}{3} \cdot \frac{3}{4} xx - 5 \cdot \frac{2}{3} x y = 8 + 2 y = 0, \frac{3}{4} x - 2 y = 0, 5 y = 8

Expand

\frac{2}{3} \cdot \frac{3}{4} xx - 5 \cdot \frac{2}{3} x y : \frac{x ^{2}}{2} - \frac{10 x y}{3}

\frac{x ^{2}}{2} - \frac{10 x y}{3} = 8

\frac{2 x ^{2} + 2 x + 10}{( x + 1 ) ( x ^{2} + 9 )}

(10 - 3) \times ((- 2, 5, 1) \times (311))

(6 x + \frac{1}{4}) (6 x - \frac{1}{4})

\frac{d ^{2}}{d x ^{2}} ((y) (3 x^{2} + 5 e^{x}))

lo g_{9} (\frac{z ^{5}}{x m ^{5}})

What is expand (2/3 x+2y=0,)(3/4 x-5y=8) ?
The solution to expand (2/3 x+2y=0,)(3/4 x-5y=8) is (x^2)/2-(10xy)/3 =8