What is expand sin(x)(4(cos(2x))^2+2cos(x)-1) ?

The solution to expand sin(x)(4(cos(2x))^2+2cos(x)-1) is 4cos^2(2x)sin(x)+sin(2x)-sin(x)

Popular >

expand sin(x)(4(cos(2x))^2+2cos(x)-1)

expand

sin (x) (4 (cos (2 x))^{2} + 2 cos (x) - 1)

4 cos^{2} (2 x) sin (x) + sin (2 x) - sin (x)

Solution steps

sin (x) (4 cos^{2} (2 x) + 2 cos (x) - 1)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

sin (x) (4 cos^{2} (2 x) + 2 cos (x) - 1) = sin (x) \cdot 4 cos^{2} (2 x) + sin (x) \cdot 2 cos (x) + sin (x) (- 1)

= sin (x) \cdot 4 cos^{2} (2 x) + sin (x) \cdot 2 cos (x) + sin (x) (- 1)

Simplify

sin (x) \cdot 4 cos^{2} (2 x) + sin (x) \cdot 2 cos (x) + sin (x) (- 1) : 4 cos^{2} (2 x) sin (x) + sin (2 x) - sin (x)

= 4 cos^{2} (2 x) sin (x) + sin (2 x) - sin (x)

\frac{d}{d t} ((x) (3 x + 2 y + 4 z))

4 (9 + x^{2}) + 5 (4 - x)

(1 + sec (θ))^{2}

\frac{( x + 5 ) ^{3}}{3}

\frac{e ^{2 x} ( 5 e ^{3 x} - 2 )}{25}

What is expand sin(x)(4(cos(2x))^2+2cos(x)-1) ?
The solution to expand sin(x)(4(cos(2x))^2+2cos(x)-1) is 4cos^2(2x)sin(x)+sin(2x)-sin(x)