What is (1-1/n)(2-1/n) ?

The solution to (1-1/n)(2-1/n) is ((n-1)(2n-1))/(n^2)

Popular >

simplify (1-1/n)(2-1/n)

simplify

(1 - \frac{1}{n}) (2 - \frac{1}{n})

\frac{( n - 1 ) ( 2 n - 1 )}{n ^{2}}

Solution steps

(1 - \frac{1}{n}) (2 - \frac{1}{n})

Join

1 - \frac{1}{n} : \frac{n - 1}{n}

= \frac{n - 1}{n} (2 - \frac{1}{n})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( n - 1 ) ( 2 - \frac{1}{n} )}{n}

Simplify

(n - 1) (2 - \frac{1}{n}) : \frac{( n - 1 ) ( 2 n - 1 )}{n}

= \frac{\frac{( n - 1 ) ( 2 n - 1 )}{n}}{n}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( n - 1 ) ( 2 n - 1 )}{nn}

Apply exponent rule:

aa = a^{2}

nn = n^{2}

= \frac{( n - 1 ) ( 2 n - 1 )}{n ^{2}}

(2 u^{2} + 2 v^{2}) 2 u^{2} + 2 v^{2} + 4

(3 - 1 - 4 x) (3 + 1 - 4 x)

(4 + sin (θ))^{2}

lo g_{10} (3 \frac{x}{z})

(x + \frac{2}{5}) (12 x^{2} - 12 x^{3})