What is expand (-w^2t-lcos(θ)w^2)(lsin(θ)) ?

The solution to expand (-w^2t-lcos(θ)w^2)(lsin(θ)) is -w^2ltsin(θ)-l^2w^2cos(θ)sin(θ)

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expand (-w^2t-lcos(θ)w^2)(lsin(θ))

expand

(- w^{2} t - l cos (θ) w^{2}) (l sin (θ))

- w^{2} lt sin (θ) - l^{2} w^{2} cos (θ) sin (θ)

Solution steps

(- w^{2} t - l cos (θ) w^{2}) (l sin (θ))

= (l sin (θ)) (- w^{2} t - l cos (θ) w^{2})

Apply the distributive law:

a (b - c) = ab - a c

(l sin (θ)) (- w^{2} t - l cos (θ) w^{2}) = l sin (θ) (- w^{2} t) - l sin (θ) l cos (θ) w^{2}

= l sin (θ) (- w^{2} t) - l sin (θ) l cos (θ) w^{2}

Simplify

l sin (θ) (- w^{2} t) - l sin (θ) l cos (θ) w^{2} : - w^{2} lt sin (θ) - l^{2} w^{2} cos (θ) sin (θ)

= - w^{2} lt sin (θ) - l^{2} w^{2} cos (θ) sin (θ)

2 (8 + 3 + 6)

∣ (1 - a c - b d) + (b c - a d) i ∣

\frac{3}{s + 2} + \frac{7 s + 4}{s ^{2} - 2 s + 2}

\frac{1}{( 1 - x ) ^{3} ( 1 + x ) ( 1 - x ^{5} )}

(2 x^{2} - \frac{1}{4 x})^{8}

What is expand (-w^2t-lcos(θ)w^2)(lsin(θ)) ?
The solution to expand (-w^2t-lcos(θ)w^2)(lsin(θ)) is -w^2ltsin(θ)-l^2w^2cos(θ)sin(θ)