What is expand (x-7)/((x+2)(x-1)) ?

The solution to expand (x-7)/((x+2)(x-1)) is (x-7)/(x^2+x-2)

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expand (x-7)/((x+2)(x-1))

expand

\frac{x - 7}{( x + 2 ) ( x - 1 )}

\frac{x - 7}{x ^{2} + x - 2}

Solution steps

\frac{x - 7}{( x + 2 ) ( x - 1 )}

Expand

(x + 2) (x - 1) : x^{2} + x - 2

= \frac{x - 7}{x ^{2} + x - 2}

\frac{\frac{d}{d x} ( - x ^{2} + 2 )}{( x ^{2} + 2 ) ^{2}}

\frac{1}{2 ( 2 ln ( 2 ) + 1 )}

(3 x^{6} - x^{3} + 3) (\frac{x ^{4}}{3} + \frac{x}{9} - \frac{7}{3})

\frac{1}{( 1 - x y ) ^{2}}

\frac{1}{( x + 1 ) ^{2} ( x ^{2} + 4 y + 13 )}

What is expand (x-7)/((x+2)(x-1)) ?
The solution to expand (x-7)/((x+2)(x-1)) is (x-7)/(x^2+x-2)