What is expand ((3x+1)^3)/6 ?

The solution to expand ((3x+1)^3)/6 is (9x^3)/2+(9x^2)/2+(3x)/2+1/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((3x+1)^3)/6

expand

\frac{( 3 x + 1 ) ^{3}}{6}

\frac{9 x ^{3}}{2} + \frac{9 x ^{2}}{2} + \frac{3 x}{2} + \frac{1}{6}

Solution steps

\frac{( 3 x + 1 ) ^{3}}{6}

(3 x + 1)^{3} = 27 x^{3} + 27 x^{2} + 9 x + 1

= \frac{27 x ^{3} + 27 x ^{2} + 9 x + 1}{6}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{27 x ^{3} + 27 x ^{2} + 9 x + 1}{6} = \frac{27 x ^{3}}{6} + \frac{27 x ^{2}}{6} + \frac{9 x}{6} + \frac{1}{6}

= \frac{27 x ^{3}}{6} + \frac{27 x ^{2}}{6} + \frac{9 x}{6} + \frac{1}{6}

Cancel

\frac{27 x ^{3}}{6} : \frac{9 x ^{3}}{2}

= \frac{9 x ^{3}}{2} + \frac{27 x ^{2}}{6} + \frac{9 x}{6} + \frac{1}{6}

Cancel

\frac{27 x ^{2}}{6} : \frac{9 x ^{2}}{2}

= \frac{9 x ^{3}}{2} + \frac{9 x ^{2}}{2} + \frac{9 x}{6} + \frac{1}{6}

Cancel

\frac{9 x}{6} : \frac{3 x}{2}

= \frac{9 x ^{3}}{2} + \frac{9 x ^{2}}{2} + \frac{3 x}{2} + \frac{1}{6}

(20 3 - 0.4 h - 4 h)^{2}

(t + e^{2 t})^{2}

6 (1 + 43)

4 \cdot (27 x) (- 2 y)

(1 - 5)^{4}

What is expand ((3x+1)^3)/6 ?
The solution to expand ((3x+1)^3)/6 is (9x^3)/2+(9x^2)/2+(3x)/2+1/6