What are the solutions to the equation x^2=(4x^2-6x+3) ?

The solutions to the equation x^2=(4x^2-6x+3) are x=1

Find the zeros of x^2=(4x^2-6x+3)

The zeros of x^2=(4x^2-6x+3) are x=1

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x^{2} = (4 x^{2} - 6 x + 3)

x = 1

Solution steps

x^{2} = (4 x^{2} - 6 x + 3)

Refine

x^{2} = 4 x^{2} - 6 x + 3

Switch sides

4 x^{2} - 6 x + 3 = x^{2}

Move

x^{2}

to the left side

3 x^{2} - 6 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 \cdot 3 = 0

x_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 3}

x = \frac{- ( - 6 )}{2 \cdot 3}

\frac{- ( - 6 )}{2 \cdot 3} = 1

x = 1

The solution to the quadratic equation is:

x = 1

5 = \frac{x}{2}

∣ x - 7 ∣ + 5 = 17

5 x = 28

5 x^{2} = 245

∣ - 9 - 7 x ∣ = ∣ 23 - 7 x ∣

What are the solutions to the equation x^2=(4x^2-6x+3) ?
The solutions to the equation x^2=(4x^2-6x+3) are x=1
Find the zeros of x^2=(4x^2-6x+3)
The zeros of x^2=(4x^2-6x+3) are x=1