What is expand ln(x-1)(x+2) ?

The solution to expand ln(x-1)(x+2) is xln(x-1)+2ln(x-1)

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expand ln(x-1)(x+2)

expand

ln (x - 1) (x + 2)

x ln (x - 1) + 2 ln (x - 1)

Solution steps

ln (x - 1) (x + 2)

Apply the distributive law:

a (b + c) = ab + a c

a = ln (x - 1), b = x, c = 2

= ln (x - 1) x + ln (x - 1) \cdot 2

= x ln (x - 1) + 2 ln (x - 1)

(x - 2)^{6}

arcsin (\frac{1}{3} \cdot (x - 2))

- \frac{5 ( 13 - X )}{2}

(t sin (t^{2})) (2 t^{2} cos (t^{2}) + sin (t^{2}))

\frac{π ( 63 t + 22 )}{9 t ^{2} + 12 t + 4}

What is expand ln(x-1)(x+2) ?
The solution to expand ln(x-1)(x+2) is xln(x-1)+2ln(x-1)