What is t(x)x^{''}-(t(x)+2)x^'+2x ?

The solution to t(x)x^{''}-(t(x)+2)x^'+2x is tx^{1+'^2}-x^'(tx+2)+2x

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simplify t(x)x^{''}-(t(x)+2)x^'+2x

simplify

t (x) x^{^{''}} - (t (x) + 2) x^{^{'}} + 2 x

t x^{1 +'^{2}} - x^{'} (t x + 2) + 2 x

Solution steps

t (x) x^{^{''}} - (t (x) + 2) x^{^{'}} + 2 x

Remove parentheses:

(a) = a

= t x x^{^{^{''}}} - (t x + 2) x^{^{^{'}}} + 2 x

125 (π + 2)

(x + h x)^{2} + 1

\frac{- 10 x ^{4} + 220 x - 810}{( x ^{2} - 9 ) ^{3}}

(5 - \frac{1}{5}) (5 + \frac{1}{5})

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What is t(x)x^{''}-(t(x)+2)x^'+2x ?
The solution to t(x)x^{''}-(t(x)+2)x^'+2x is tx^{1+'^2}-x^'(tx+2)+2x