What is expand (kx^3+x^2+k^2x+3k^2+11)/(x(x^2-3x)) ?

The solution to expand (kx^3+x^2+k^2x+3k^2+11)/(x(x^2-3x)) is (kx^3+x^2+k^2x+3k^2+11)/(x^3-3x^2)

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expand (kx^3+x^2+k^2x+3k^2+11)/(x(x^2-3x))

expand

\frac{k x ^{3} + x ^{2} + k ^{2} x + 3 k ^{2} + 11}{x ( x ^{2} - 3 x )}

\frac{k x ^{3} + x ^{2} + k ^{2} x + 3 k ^{2} + 11}{x ^{3} - 3 x ^{2}}

Solution steps

\frac{k x ^{3} + x ^{2} + k ^{2} x + 3 k ^{2} + 11}{x ( x ^{2} - 3 x )}

Expand

x (x^{2} - 3 x) : x^{3} - 3 x^{2}

= \frac{k x ^{3} + x ^{2} + k ^{2} x + 3 k ^{2} + 11}{x ^{3} - 3 x ^{2}}

A (2, - 6, - 3) B (4, 3, 1)

3 x (3 x + 3Δ x)

(21 - 8 i) (1 - 2 i)

6 \cdot (\frac{1}{2} - \frac{1}{2})

\frac{1}{x ( 2 x + 1 )}

What is expand (kx^3+x^2+k^2x+3k^2+11)/(x(x^2-3x)) ?
The solution to expand (kx^3+x^2+k^2x+3k^2+11)/(x(x^2-3x)) is (kx^3+x^2+k^2x+3k^2+11)/(x^3-3x^2)