What is the d/(dt)((x)(3t^2-8)) ?

The d/(dt)((x)(3t^2-8)) is (dx)/(dt)(3t^2-8)+6tx

What is the first d/(dt)((x)(3t^2-8)) ?

The first d/(dt)((x)(3t^2-8)) is (dx)/(dt)(3t^2-8)+6tx

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} ((x) (3 t^{2} - 8))

\frac{d x}{d t} (3 t^{2} - 8) + 6 t x

Solution steps

\frac{d}{d t} ((x) (3 t^{2} - 8))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = 3 t^{2} - 8

= \frac{d x}{d t} (3 t^{2} - 8) + \frac{d}{d t} (3 t^{2} - 8) x

\frac{d}{d t} (3 t^{2} - 8) = 6 t

= \frac{d x}{d t} (3 t^{2} - 8) + 6 t x

\frac{( x - 4 ) ^{3}}{3}

3 + (- 2) i

- e^{t} (cos (t) - sin (t))

x^{\frac{4}{5}} (5 x - 20)^{2}

((\frac{3590675}{13422})^{\frac{1}{16}} - 1) \cdot 100

What is the d/(dt)((x)(3t^2-8)) ?
The d/(dt)((x)(3t^2-8)) is (dx)/(dt)(3t^2-8)+6tx
What is the first d/(dt)((x)(3t^2-8)) ?
The first d/(dt)((x)(3t^2-8)) is (dx)/(dt)(3t^2-8)+6tx