What is implicit (dy)/(dx),x^2-y^2=1 ?

The answer to implicit (dy)/(dx),x^2-y^2=1 is (dy)/(dx)= x/y

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implicit (dy)/(dx),x^2-y^2=1

implicit derivative

\frac{d y}{d x}, x^{2} - y^{2} = 1

\frac{d y}{d x} = \frac{x}{y}

Solution steps

x^{2} - y^{2} = 1

Treat

y

y (x)

Differentiate both sides:

2 x - 2 y \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{x}{y}

\frac{d y}{d x} = \frac{x}{y}

(1 + tan (x))^{4}

a (2 x e^{3 x} + e^{3 x} \cdot 3 x^{2}) - b sin (x) + d cos (x)

(- 4, - 2) y (- 2, - 8)

so l v e (51.64 \cdot x^{3} + 2 \cdot x - 0.9125, x)

(\frac{1}{x} - x)^{5}

What is implicit (dy)/(dx),x^2-y^2=1 ?
The answer to implicit (dy)/(dx),x^2-y^2=1 is (dy)/(dx)= x/y